sjs/gh-XcodesOrg-XcodesApp
1
0
Fork 0
mirror of https://github.com/XcodesOrg/XcodesApp.git synced 2026-03-25 08:55:46 +00:00
Code Issues Projects Releases Packages Wiki Activity Actions

Remove invalid phone number index error

Browse source 
Not relevant for Xcodes.app.
This commit is contained in:
Brandon Evans 2021-01-25 19:10:06 -07:00
parent 6b5a64010e
commit 9508cda585
No known key found for this signature in database
GPG key ID: D58A4B8DB64F8E93
1 changed files with 0 additions and 3 deletions
Show stats Download patch file Download diff file Expand all files Collapse all files

3
Xcodes/AppleAPI/Sources/AppleAPI/Client.swift
View file

@ -175,7 +175,6 @@ public enum AuthenticationState: Equatable {
public enum AuthenticationError: Swift.Error, LocalizedError, Equatable {
case invalidSession
case invalidUsernameOrPassword(username: String)
case invalidPhoneNumberIndex(min: Int, max: Int, given: String?)
case incorrectSecurityCode
case unexpectedSignInResponse(statusCode: Int, message: String?)
case appleIDAndPrivacyAcknowledgementRequired
@ -189,8 +188,6 @@ public enum AuthenticationError: Swift.Error, LocalizedError, Equatable {
return "Invalid username and password combination. Attempted to sign in with username \(username)."
case .appleIDAndPrivacyAcknowledgementRequired:
return "You must sign in to https://appstoreconnect.apple.com and acknowledge the Apple ID & Privacy agreement."
case .invalidPhoneNumberIndex(let min, let max, let given):
return "Not a valid phone number index. Expecting a whole number between \(min)-\(max), but was given \(given ?? "nothing")."
case .accountUsesTwoStepAuthentication:
return "Received a response from Apple that indicates this account has two-step authentication enabled. xcodes currently only supports the newer two-factor authentication, though. Please consider upgrading to two-factor authentication, or open an issue on GitHub explaining why this isn't an option for you here: https://github.com/RobotsAndPencils/xcodes/issues/new"
case .accountUsesUnknownAuthenticationKind: